Spring 2.5.6 Basic Example


Creating the Project

  • Open Eclipse (Kepler)
  • New -> Maven Project
  • Simple Project
  • Group Id: com.skills421.examples.spring
  • Artifact Id: Spring2.5.6Example
  • Finish

pom.xml

<project xmlns="http://maven.apache.org/POM/4.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://maven.apache.org/POM/4.0.0 http://maven.apache.org/xsd/maven-4.0.0.xsd">
<modelVersion>4.0.0</modelVersion>
<groupId>com.skills421.examples.spring</groupId>
<artifactId>Spring2.5.6Example</artifactId>
<version>0.0.1-SNAPSHOT</version>
<dependencies>
<!-- Spring framework -->
<dependency>
<groupId>org.springframework</groupId>
<artifactId>spring</artifactId>
<version>2.5.6</version>
</dependency>
</dependencies>
</project>

Person bean

src/main/java
com.skills421.examples.spring.model.Person

package com.skills421.examples.spring.model;

public class Person
{
private String name;
private int age;

public String getName()
{
return name;
}
public void setName(String name)
{
this.name = name;
}
public int getAge()
{
return age;
}
public void setAge(int age)
{
this.age = age;
}

public String toString()
{
StringBuilder sb = new StringBuilder();

sb.append("Person[");
sb.append("name=");
sb.append(this.getName());
sb.append(", age=");
sb.append(this.getAge());
sb.append("]");

return sb.toString();

}
}

ApplicationContext

src/main/resources
ApplicationContext.xml

<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

<bean id="johnDoe" class="com.skills421.examples.spring.model.Person">
<property name="name" value="Jon Doe" />
<property name="age" value="21" />
</bean>
</beans>

Main

src/main/java
com.skills421.examples.spring.Main

package com.skills421.examples.spring;

import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;

import com.skills421.examples.spring.model.Person;

public class Main
{

public static void main(String[] args)
{
ApplicationContext context = new ClassPathXmlApplicationContext("ApplicationContext.xml");

Person p1 = (Person) context.getBean("johnDoe");
System.out.println(p1.toString());
}
}

Output

Person[name=Jon Doe, age=21]

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out /  Change )

Google photo

You are commenting using your Google account. Log Out /  Change )

Twitter picture

You are commenting using your Twitter account. Log Out /  Change )

Facebook photo

You are commenting using your Facebook account. Log Out /  Change )

Connecting to %s

Up ↑

%d bloggers like this: